21laila21
21laila21 21laila21
  • 19-07-2020
  • Mathematics
contestada

Evaluate
[tex]lim \: \frac{ \frac{1}{ \sqrt{x} } - 1}{ \sqrt{x} - 1} \: as \: x \: approaches \: 1[/tex]
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Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 19-07-2020

Answer:

  -1

Step-by-step explanation:

In many cases, the simplified expression is not undefined at the point of interest.

  [tex]\dfrac{\left(\dfrac{1}{\sqrt{x}}-1\right)}{\sqrt{x}-1}=\dfrac{\left(\dfrac{1-\sqrt{x}}{\sqrt{x}}\right)}{\sqrt{x}-1}=\dfrac{-1}{\sqrt{x}}[/tex]

This can be evaluated at x=1:

  -1/√1 = -1

Then, the limit is ...

  [tex]\boxed{\lim\limits_{x\to 1}\dfrac{\left(\dfrac{1}{\sqrt{x}}-1\right)}{\sqrt{x}-1}=-1}[/tex]

__

A graph confirms this conclusion.

Ver imagen sqdancefan
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