A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a constant leftward acceleration of magnitude 0.50 m/s^2 over 14 m. What is the velocity of the basketball after rolling for 14 m?

Respuesta :

u= 4m/s

a= -0.50m/s^2

S=14m

v^2=u^2-2as

v^2=(16-14)m/s

v=√2m/s

Answer:

1.4

Explanation:

I just did it