Answer:
[tex]\boxed{B'C' = 15}[/tex]
Step-by-step explanation:
Scale Factor = 3
Using Formula:
Scale Factor = [tex]\frac{LengthOfDilatedTriangle}{Length of Actual Triangle}[/tex]
Scale Factor = [tex]\frac{B'C'}{BC}[/tex]
Where Scale Factor = 3, BC = 5
So,
B'C' = 3 * 5
B'C' = 15
