Answer:
Step-by-step explanation:
Hello,
We just need to apply the formula using the discriminant
[tex]-6x^2-2x+1=0\\\\\Delta = b^2-4ac = (-2)^2-*4(-6)*1=4+24=28[/tex]
so we have two distinct real solutions
[tex]x_1=\dfrac{2+\sqrt{28}}{2*(-6)}=\dfrac{2+2\sqrt{7}}{2*(-6)}=-\dfrac{\sqrt{7}+1}{6} \\\\ and \\\\x_2=\dfrac{\sqrt{7}-1}{6}[/tex]
Hope this helps
