Answer:
[tex]\dfrac{2xy+x}{3y+2}[/tex]
Step-by-step explanation:
Factor numerator and denominator and cancel common factors.
[tex]\dfrac{3x-12xy^2}{6-3y-18y^2}=\dfrac{-3x(4y^2-1)}{-3(6y^2+y-2)}=\dfrac{x(2y-1)(2y+1)}{(2y-1)(3y+2)}\\\\=\boxed{\dfrac{2xy+x}{3y+2}}[/tex]
