Answer:
Step-by-step explanation:
log(x²+8)=1+log(x)
log(x²+8)-log(x)=1
[tex]log\frac{x^2+8}{x} =1\\\frac{x^2+8}{x} =10^1\\x^2+8=10x\\x^2-10x+8=0\\x=\frac{10 \pm \sqrt{(-10)^2-4*1*8} }{2} \\=\frac{10 \pm \sqrt{100-32} }{2} \\=\frac{10 \pm \sqrt{68} }{2} \\=\frac{10 \pm 2\sqrt{17} }{2} \\=5 \pm \sqrt{17}[/tex]
