Answer:
x = 8
Step-by-step explanation:
Perhaps you want to solve ...
[tex]\dfrac{4x+3}{8x-1}=\dfrac{5}{9}\\\\9(4x+3)=5(8x-1)\qquad\text{multiply by $9(8x-1)$}\\\\36x+27=40x-5\qquad\text{eliminate parentheses}\\\\32=4x\qquad\text{add $5-36x$}\\\\\boxed{x=8}\qquad\text{divide by 4}[/tex]
