Answer:
[tex]$ \frac{6x^2-5x+15 }{x^2-3x} $[/tex]
Step-by-step explanation:
[tex]$\frac{6x}{x-3} -\frac{5}{x} $[/tex]
[tex]$\frac{6x(x)}{x(x-3)} -\frac{5(x-3)}{x(x-3)} $[/tex]
[tex]$\frac{6x^2}{x^2-3x} -\frac{5x-15}{x^2-3x} $[/tex]
[tex]$ \frac{6x^2-5x+15 }{x^2-3x} $[/tex]
