Answer:
every equivalent to 6 ≤ x
Step-by-step explanation:
We can subtract 5+11/6x to get ...
7 ≤ -(11/6)x +3x = (7/6)x
Multiplying by 6/7 gives ...
6 ≤ x
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When x is in the set of real numbers, x in any real number that is 6 or more.
When x is in the set of integers, x is any integer that is 6 or more: {6, 7, 8, ...}.
When no set is specified, the solution is simply ...
6 ≤ x
