Answer:
(-3,18) and (-1,6)
Step-by-step explanation:
[tex]x^2-2x+3=-6x\\<=> x^2+4x+3 = 0\\<=> (x+2)^2 -4+3=0\\<=> (x+2)^2-1^2 = 0\\<=> (x+2+1)(x+2-1) = 0\\<=> (x+1)(x+3) = 0\\<=> x+1 = 0 \ or \ x+3 = 0\\<=> x = -1 \ or \ x=-3[/tex]
so the solutions are
(-3,-6*-3=18) that we can write (-3,18)
and
(-1,-6*-1=6) that we can write (-1,6)
