Respuesta :

jaimemenendezalvarez

Answer: [tex]y = \frac{x-1}{x+1}[/tex]

Step-by-step explanation:

[tex]log(1+y) - log(1-y) = log x \\log\frac{1+y}{1-y} =log x\\x = \frac{1+y}{1-y}\\x(1-y)=1+y\\x-xy=1+y\\x-1 = xy+y\\y(x+1)=x-1\\y=\frac{x-1}{x+1}[/tex]
Express y in terms of x.

Log (1+y) - Log (1-y) = Log x

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