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19-06-2020
Mathematics

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One number is 11 less than the other number. If their sum is increased by 8, the result is 71. Find the numbers.

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09pqr4sT 09pqr4sT

19-06-2020

First number = [tex]x[/tex]

Second number = [tex]x-11[/tex]

[tex]x+x-11+8=71[/tex]

[tex]2x-3=71[/tex]

[tex]2x=71+3[/tex]

[tex]2x=74[/tex]

[tex]x=37[/tex]

First number = [tex]x=37[/tex]

Second number = [tex]x-11=37-11=26[/tex]

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