Respuesta :

osikbro

Answer:

p+q

Step-by-step explanation:

[tex]\dfrac{p^2-q^2}{p+q}\div\dfrac{p-q}{p+q}= \\\\\\\dfrac{(p-q)(p+q)}{p+q}\times \dfrac{p+q}{p-q}= \\\\\\\dfrac{(p-q)(p+q)}{p-q}= \\\\\\p+q[/tex]

Hope this helps!

bbooobb

Answer:

p+q

Step-by-step explanation:

We can use difference of squares to make the fractions

[tex]\frac{(p+q)(p-q)}{(p+q)} *\frac{p+q}{p-q}[/tex]

Since dividing is the same as multiplying bt the reciprocal

The (p+q) and the (p-1) cancel out so we are left with (p+q)