Answer:
Step-by-step explanation:
real zeros -----> where f(x) = 0
[tex]-2x^{2} - 6x - 1 = 0\\[/tex] * (-1)
[tex]2x^{2} + 6x + 1 = 0\\[/tex]
Δ = [tex]6^{2} - 4 * 2 * 1[/tex] = 36 - 8 = 28
vΔ = 2[tex]\sqrt{7}[/tex]
x' = [tex]\frac{-6 + 2\sqrt{7} }{2 * 2} = \frac{-6 +2\sqrt{7} }4}[/tex]
x'' = [tex]\frac{-6 - 2\sqrt{7} }{2 * 2} = \frac{-6 -2\sqrt{7} }4}[/tex]
