Answer:
The value of the limit is [tex]\frac{9}{2}[/tex]
Step-by-step explanation:
When we are working with limits in which the variable goes to infinity, we only take the highest order factor of the numerator and of the denominator.
So we have
[tex]$\lim_{t \to +\infty} \frac{9n^{3}}{2n^{3}}$[/tex]
We can simplify the cubes.
[tex]$\lim_{t \to +\infty} \frac{9}{2}$[/tex]
The limit of a constant is the proper constant.
So the value of the limit is [tex]\frac{9}{2}[/tex]
