Answer:[tex]v=4.42\ m/s[/tex]
Explanation:
Given
Child falls a height of [tex]h=1\ m[/tex]
Applying conservation of energy we can write
Loss in Potential energy=Gain in kinetic energy
[tex]mgh=\frac{1}{2}mv^2[/tex]
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 1}[/tex]
[tex]v=\sqrt{19.6}[/tex]
[tex]v=4.42\ m/s[/tex]
Thus child reaches a velocity of 4.42 m/s
