Respuesta :

osikbro

Answer:

B

Step-by-step explanation:

[tex]2x^2+16x-8=0[/tex]

[tex]x=\dfrac{-16\pm \sqrt{256+64}}{4}=\dfrac{-16\pm 8\sqrt{5}}{4}=-4\pm 2\sqrt{5}[/tex], or answer choice B. Hope this helps!

TREKKER

Answer:

B

Step-by-step explanation:

2x^2 + 16x - 8 = 0 -->

x^2 + 8x - 4 = 0-->

(-b +/- sqrt(b^2 - 4ac))/2 -->

(-8 +/- sqrt(64 - (-4 * 4)))/2 -->

(-8 +/- sqrt(80))/2 -->

(-8 +/- 4sqrt5)/2 -->

-4 +/- 2sqrt5 (B)

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