The diagonal of a rhombus divides it into two congruent isosceles triangles.
So ∠CBD ≅ ∠CDB
∠CBD + ∠CDB + 68 = 180
2∠CBD = 180 - 68 = 112
∠CBD = 56
We also have
∠BDE + ∠E + ∠DBE = 180
∠DBE = 180 - 73 - 36 = 71
∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15
Answer: ∠EBC = 15 degrees
