Answer:
Explanation:
100 mL of a .5 M solution
= 0.1 L of .5 M solution
This solution will contain .1 x .5 mole of solute
= .05 mole of solute
molecular weight of CuSO₄
= 63.5 + 32 + 64
= 159.5 gm
one mole of CuSO₄ = 159.5 gm
.05 mole = 159.5 x .05 gm
= 7.975 gm
7.975 gm of CuSO₄ will be required .
