Using the formula
[tex]a^2-b^2=(a+b)(a-b)[/tex]
We can write
[tex](4^2)^2-1 = 16^2-1 = (16+1)(16-1)=17\cdot 15[/tex]
Since 17 is prime and the factors of 15 are 3 and 5, the three prime factors of this number are 3, 5 and 17.
Answer:{Redacted)
Step-by-step explanation:{Redacted}
Used the wrong formula.
Wish there was a delete option...
