Respuesta :

Answer:

Step-by-step explanation:

[tex]slope~of~line~PQ=\frac{11-6}{9-7}=\frac{5}{2}\\slope~of~line~RS,~m2=\frac{4-9}{7-5}=-\frac{5}{2} \\m1 \times m2=\frac{5}{2} \times -\frac{5}{2} =-\frac{25}{4} \neq -1[/tex]

so lines are not perpendicular.

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