Answer:
[tex]pOH=11.2[/tex]
Explanation:
Hello,
In this case, by knowing that the pOH is defined in terms of the concentration of OH⁻ as shown below:
[tex]pOH=-log([OH^-])[/tex]
We directly compute with the given concentration:
[tex]pOH=-log(6.5x10^{-12})\\\\pOH=11.2[/tex]
Moreover, fur such pOH, the pH will be:
[tex]pH=14-11.2=2.8[/tex]
Which means that such solution is an acid solution.
Best regards.
