Answer:
Step-by-step explanation:
Let m be the mass of the vehicle
frictional force = μ mg
μ is coefficient of friction ,
deceleration = μ g
= .97 x 32
a = - 31.04 ft /s
v² = u² - 2 a s
0 = u² - 2 a s
u² = 2 a s
= 2 x 31.04 x 63
= 3911.04
u = 62.54 ft / s
