Answer:
[tex]2\sqrt[3]{2}[/tex]
Step-by-step explanation:
[tex]log_{2}x + log_{4}x = 2\\\\log_{2}x + \frac{log_{2}x}{log_{2}4} =2\\\\log_{2}x + \frac{log_{2}x}{2} =2\\\\2log_{2}x + log_{2}x =4\\\\3log_{2}x =4\\\\log_{2}x = \frac{4}{3} \\\\x=2^{\frac{4}{3}}=2^{1+\frac{1}{3} }=2*2^{\frac{1}{3} }=2\sqrt[3]{2}[/tex]
