Answer:
x-3/x+4 ÷ x^2-1/x ; x ≠ -4, 0
Step-by-step explanation:
x-3/x+4 ÷ x^2-1/x --> x ≠ -4, 0 (because the denominators would be 0 if x = -4 or 0)-->
(x-3)/(x-4) * x/(x^2-1) -->
((x-3)(x))/((x-4)(x-1)(x+1))-->
No way to simplify it further-->
x-3/x+4 ÷ x^2-1/x
