Answer:
The equivalent resistance of the combination is 3.42 ohms.
Explanation:
We have,
8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.
For a parallel combination, the equivalent resistance is given by :
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}[/tex]
Plugging the values of R₁ and R₂, we get :
[tex]\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega[/tex]
So, the equivalent resistance of the combination is 3.42 ohms.
