[tex]\dfrac{6x-1}{5}=\dfrac{3}{1}\ \ \ \ |cross\ multiply\\\\1(6x-1)=5\cdot3\\\\6x-1=15\ \ \ \ |add\ 1\ to\ both\ sides\\\\6x=16\ \ \ \ |divide\ both\ sides\ by\ 6\\\\x=\dfrac{16}{6}\\\\x=\dfrac{16:2}{6:2}\\\\x=\dfrac{8}{3}\\\\Answer:\boxed{x=\frac{8}{3}=2\frac{2}{3}}[/tex]
