Answer:
Which set of side lengths is a Pythagorean triple? 9, 40, 41
Step-by-step explanation:
[tex] c = \sqrt{ {a}^{2} + {b}^{2} } [/tex]
9 = a
40 = b
41 = c
[tex]c = \sqrt{ {a}^{2} + {b}^{2} } \\ c = \sqrt{ {9}^{2} + {40}^{2} } \\ c = \sqrt{81 + 1.600} \\ c = \sqrt{1.681} \\ c = 41[/tex]
