Respuesta :

princedavidanicet6

Answer:

given that

....the mass of the metal is 20g(0.02kg)

....specific heat capacity(c) is 0.4J/g°C

....ΔT=??

heat(Q)=3.9KJ(3900J)

Q=mcΔT

ΔT= Q/mc

.....=3900÷(20g x 0.4J/g°C)

.....=487.5°C

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