Answer:
The vertex is at (h, k) => (1, 3)
Step-by-step explanation:
Complete the square of y=x^2 - 2x + 4 to determine the coordinates of the vertex.
Note that the first two terms of y=x^2 - 2x + 4 resemble the perfect square (x - 1)^2:
y=x^2 - 2x + 4 => y= ( x^2 - 2x + 1 )+ 4 - 1, or
y = (x - 1)^2 + 3
Comparing this last result to the standard equation y = (x - h)^2 + k, we see that h = 1 and k = 3. The vertex is at (h, k) => (1, 3)
