Answer:
[tex]cos(G)=\frac{28}{53}[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle EFG
[tex]cos(G)=\frac{GF}{EG}[/tex] ----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
[tex]cos(G)=\frac{28}{53}[/tex]
