Answer:
Putting the value of x= 2 in the first equation,
6(2)+y= 17
y= 17-12 = 5
This value is same as the value for y given in the question.
Therefore, it satisfies the equation.
Again, putting the value of x= 2 in the second equation,
3(2)+14y= 16
14y= 16-6 = 10
y= 10/14 = 5/7
It doesn't satisfies the 2nd equation
Hence, (2,5) is not the solution to this system.
