Answer:
Correct Answer is D.
Step-by-step explanation:
Solve for tanx,
3tan2x−√3tanx=0
√3tanx(√3tanx−1)=0
Thus tanx=0,tanx=1√3
For tan x =0, the principal solution is x=0,π
For tanx=1√3, the principal solution would be x=π/6,7π/6
