Answer:
Step-by-step explanation:
The angle inscribed in a semicircle is always 90°
∠ABC = 90°
In ΔABC,
∠A + ∠B + ∠C = 180
34 + 90 + ∠C = 180
124+ ∠C = 180
∠C = 180 - 124
∠C = 56°
InΔBDC, given that BD = BC
Therefore, ∠ BDC = ∠C
∠BDC = 56°
In ΔABD, external angle is equal to the sum of opposite interior angles.
∠DBA + ∠A = ∠BDC
x + 34° = 56°
x = 56° - 34°
x = 22°
