Answer:
No real solutions.
Step-by-step explanation:
Square both sides:
[tex] x-3=(x-1)^2\\
x-3=x^2-2x+1\\
x^2-3x+4=0[/tex]
Evaluate the discriminant:
$\Delta =3^2-4 \times 1 \times 4$
$= 9-16=-7<0$
Since $\Delta $ is less than zero, there are no real solutions.
