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16-04-2020
Mathematics

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Consider j(x) = 2x - 5
Find j^-1(x) algebraically.

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varyab11 varyab11

16-04-2020

Answer:

j^-1(x) = 1/2(x+5)

Step-by-step explanation:

1. Replace j(x) with y to make it easier

y = 2x - 5

2. Switch the places of x and y

x = 2y - 5

3. Solve for y

x + 5 = 2y

y = 1/2(x+5)

4. Replace y with j^-1(x)

j^-1(x) = 1/2(x+5)

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