Answer:
2.4 litters of water are required.
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
Now we will put the values in above given formula.
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
