Answer:
[tex] 22\sqrt 2 [/tex] cm
Step-by-step explanation:
[tex] in \: a \: 45 \degree - 45 \degree - 45 \degree \: \triangle \\ leg = \frac{1}{ \sqrt{2} } \times hypotenuse \\ \\ \therefore \: 22 = \frac{1}{ \sqrt{2} } \times hypotenuse \\ \\ \purple{ \bold{ \therefore \: hypotenuse = 22 \sqrt{2} cm}}[/tex]
