Explanation:
Case 1,
A force F is pushing perpendicular on an object a distance L/2 from the rotation axis. Torque is given by :
[tex]\tau_1=Fd\sin \theta\\\\\tau_1=\dfrac{FL}{2}\sin (90)\\\\\tau_1=\dfrac{FL}{2}\ ..........(1)[/tex]
Case 2,
The same force is pushing at an angle of 30 degrees a distance L from the axis. New torque is given by :
[tex]\tau_2=Fd\sin \theta\\\\\tau_2=FL\sin (30)\\\\\tau_2=\dfrac{FL}{2}\ ..........(2)[/tex]
From equation (1) and (2), it is clear that the force in both cases is same.
