Respuesta :

caylus
Hello,

1)
sin x=3/5==>x=126.869897...° (since in quadrant II)

2)==>cos x<0
cos x=-√(1-sin ² x)=-√(1-9/25)=-4/5

tan x=(3/5)/(-4/5)=-3/4

cotg x=-4/3 =1/tan x

sec x=1/cos x=-5/4

cosec x=1/sin x=5/3