Respuesta :

dalendrk
[tex]\tan\theta=\dfrac{12}{5}\\\\\cos\theta=-\dfrac{5}{13}\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\tan x\cdot\cos x=\dfrac{\sin x}{\cos x}\cdot\cos x=\sin x\\\\\sin\theta=\dfrac{12}{5}\cdot\left(-\dfrac{5}{13}\right)=-\dfrac{12}{13}[/tex]

Answer:

-12/13

Step-by-step explanation:

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