Respuesta :

dalendrk
[tex]The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)-center;\ r-radius.\\-------------------\\\\(4;\ 0)\to a=4;\ b=0\\r=1\\\\\boxed{(x-4)^2+(y-0)^2=1^2\to(x-4)^2+y^2=1}[/tex]

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