The value of HF is 16.
Solution:
Given data:
GF = 20 and EF = 25
To find HF:
Using geometric mean of right triangles,
GF² = HF × EF
(20)^2 = HF × 25
400 = HF × 25
Divide by 25 on both sides.
[tex]$\frac{400}{25}=\frac{HF\times25}{25}[/tex]
16 = HF
The value of HF is 16.
