The value of ED is 2.
Solution:
Given ABC is a triangle and AC = 4
BE = EA = 2.7 and BD = DC = 2.43
It clearly shows that ED is the mid-segment of ΔABC.
By mid-segment theorem,
The segment connecting two points of the triangle is parallel to the third side and is half of that side.
⇒ ED || AC and [tex]ED = \frac{1}{2}AC[/tex]
[tex]$\Rightarrow ED = \frac{1}{2}AC[/tex]
[tex]$\Rightarrow ED = \frac{1}{2}\times 4[/tex]
⇒ ED = 2
The value of ED is 2.
