Answer:
Step-by-step explanation:
nth term = ar^(n-1)
a3 = 1/8; ar² = 1/8
a6 = 1; ar⁵ = 1
[tex]ar^{2}*r^{3}=1\\\\\frac{1}{8}*r^{3}=1\\\\r^{3}=1*8\\\\r^{3}=8\\\\r^{3}=2^{3}\\\\r=2[/tex]
[tex]ar^{2}=\frac{1}{8}\\\\a*2^{2}=\frac{1}{8}\\\\a*4=\frac{1}{8}\\\\a=\frac{1}{8*4}\\\\a=\frac{1}{32}\\\\[/tex]
