millietran18 millietran18
  • 20-03-2020
  • Mathematics
contestada

Find the limit: [tex]\lim_{x \to \ 3 }[/tex] [tex]\frac{x^3 +27}{x+3}[/tex]

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Tucon
Tucon Tucon
  • 20-03-2020

 

[tex]\displaystyle\bf\\\lim_{x\to3}\frac{x^3+27}{x+3}=\frac{3^3+27}{3+3}=\frac{27+27}{3+3}=\frac{54}{6}=\boxed{\bf9}[/tex]

 

 

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ghanami
ghanami ghanami
  • 20-03-2020

Answer:

Step-by-step explanation:

hello : here is an solution :

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