Answer:
[tex]\log_{1/13}(1/169)=2[/tex]
Step-by-step explanation:
The exponential expression b^a=c is equivalent to the log expression ...
[tex]\log_b{(c)}=a[/tex]
Filling in a=2, b=1/13, c=1/169 you get the logarithmic form ...
[tex]\boxed{\log_{1/13}(1/169)=2}[/tex]
