Answer:
-2,4/3
Step-by-step explanation:
ax²+bx+c=0
[tex]x=\frac{-b \pm\sqrt{b^2-4ac} }{2a} \\3n^2+2n-8=0\\n=\frac{-2\pm\sqrt{2^2-4*3*(-8)} }{2*3} \\n=\frac{-2 \pm \sqrt{4+96}}{6} }\\n=\frac{-2 \pm 10}{6} \\n=\frac{8}{6} =\frac{4}{3}\\or~n=\frac{-12}{6}=-2[/tex]
