Answer:
The volume is 1143,78 L
Explanation:
We use the formula PV=nRT. The conditions STP are 1 atm of pressure and 273K of temperature. We calculate the weight of 1 mol of CH4.
Weight 1 mol CH4= weight C+ (weight H)x4= 12 g + 1 g x4= 16 g/mol
16 g----1 mol CH4
817,5g--x=(817,5gx1 mol CH4)/16g= 51, 1 mol CH4
PV=nRT V=(nRT)/P
V= (51,1 mol x 0,082 l atm/K mol x 273 K)/1 atm
V= 1143,78 liters
