Answer:
0.48L of NaOH
Explanation:
Data obtained from the question include:
Number of mole of NaOH = 0.725mol
Molarity of NaOH = 1.50M
Volume of NaOH =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.725/1.5
Volume = 0.48L
Therefore, 0.48L of NaOH is needed for the reaction
